j.-a. goulet 40
4.1.4 Example: Conditional Distributions
For the beam example illustrated in figure 4.5, our prior knowledge
for the resistance {X
1
,X
2
} of two adjacent beams is
X
1
⇠N(x
1
; 500, 150
2
)[kN·m]
X
2
⇠N(x
2
; 500, 150
2
)[kN·m],
and we know that the beam resist an ce s are correl at ed wit h
⇢
12
=
0
.
8. Such a correlation could arise because both beams were fab-
ricated with the same process, in the same factory. This prior
knowledge is described by the joint bivariate Normal PD F ,
(a) Multi-beam bridge span. (Photo:
Archives Radio-Canada)
(b) Concrete beams
Figure 4.5: Example of dependence be-
tween the resistance of beams.
f
X
1
X
2
(x
1
,x
2
)=N(x; µ
X
, ⌃
X
)
8
>
>
<
>
>
:
µ
X
=
500
500
⌃
X
=
150
2
0.8 · 150
2
0.8 · 150
2
150
2
.
If we observe that the resistance of the second beam
x
2
= 700
kN·m
,
we can employ conditional probabilities t o es t i mat e t he PD F of the
strength X
1
, given the observation x
2
,
f
X
1
|x
2
(x
1
|x
2
)=N(x
1
; µ
1|2
,
2
1|2
),
where
µ
1|2
= 500 + 0.8 ⇥ 150
observation
z}|{
700 500
150
= 660 kN·m
1|2
= 150
p
1 0.8
2
= 90 kN·m.
Figure 4.6 presents the joint and conditional PDFs correspon di n g
to this example. For the joint PDF, the highlighted pink slice cor r e-
sponding to
x
2
= 700 is proportional to the conditional probability
f
X
1
|x
2
(
x
1
|x
2
= 700). If we want to obtain the conditional distribu-
tion from the joint PDF, we have to divide it by the marginal PDF
f
X
2
(
x
2
= 700). This ensures that the conditional PDF for
x
1
inte-
grates to 1. This example is trivial, yet it sets the foundations for
the more advanced models that will be pres ented in the following
chapters.
0
1,000
0
700
1,000
·10
5
x
1
x
2
f
X
1
,X
2
(x
1
,x
2
)
0
1,000
0
700
1,000
·10
3
x
1
x
2
f
X
1
|X
2
(x
1
|x
2
)
µ
1|2
=660
1|2
=90
Figure 4.6: Joint prior PDF
f
X
1
X
2
(
x
1
,x
2
)
and conditional PDF
f
X
1
|x
2
(
x
1
|x
2
)de-
scribing the resistance of beams.
4.1.5 Example: Sum of Normal Random Variables
Figure 4.7: Steel cables each made from
multiple wires. (This example is adapted
from Armen Der Kiureghian’s CE229
course at UC Berkeley.)
Figure 4.7 presents steel cables where each one is made from dozens
of individual wires. Let us consider a cable made of 50 steel wires,
each having a resistance
x
i
:
X
i
⇠N
(
x
i
; 10
,
3
2
)
kN
.Weuse
equation 4.2 to compare the cable resistance
X
cable
=
P
50
i=1
X
i
depending on th e correl at i on coefficient
⇢
ij
. With the hypothesis